Table of Contents

## What is the power dissipated by the 10 ohm resistor?

Note that the total is 120 V, the same as across the equivalent 12 Ω resistor. We can now calculate the power dissipated by each using P = I2R. For the 10 Ω resistor this is P10 = (10 A)2(10Ω) = 1000 W.

**How do you calculate the power dissipated in a resistor?**

The power dissipated by each resistor can be found using any of the equations relating power to current, voltage, and resistance, since all three are known. Let us use P=V2R P = V 2 R , since each resistor gets full voltage. Thus, P1=V2R1=(12.0 V)21.00 Ω=144 W P 1 = V 2 R 1 = ( 12.0 V ) 2 1.00 Ω = 144 W .

**How do you calculate power dissipated?**

To find out, we need to be able to calculate the amount of power that the resistor will dissipate. If a current I flows through through a given element in your circuit, losing voltage V in the process, then the power dissipated by that circuit element is the product of that current and voltage: P = I × V.

### What is the power dissipated by the 4 ohm resistor?

=>V = 4 v. hence the potential difffernce across 4 ohm resistor is 4volts. =>P = 4 Watts. Hence ,the power dissipated in 4 ohm resistor is 4 watts.

**What is power consumption in 30 ohm resistor?**

Power consumed=0.707I peak2Z. putting the values the result=35.350 J.

**What is the total rate of dissipation of electrical energy in the 12 ohm resistor?**

Question: What is the total rate of dissipation of electrical energy in the 12 ohm resistor? 12 12 w 11 = 1.0 22 17 In = 1.022 En = 12.0 V.

#### What happens to Watts in parallel?

When the bulbs are connected in parallel, each bulb has 120 V across it, each draws 1/3 A, and each dissipates 40 watts. In the series circuit, any current that flows through one bulb must go through the other bulbs as well, so each bulb draws the same current.

**How do you calculate the power rating of a resistor?**

Resistor Power (P)

- [ P = V x I ] Power = Volts x Amps.
- [ P = I2 x R ] Power = Current2 x Ohms.
- [ P = V2 ÷ R ] Power = Volts2 ÷ Ohms.

**What is maximum power dissipation?**

Power dissipation is the maximum power that the MOSFET can dissipate continuously under the specified thermal conditions. It is defined between channel (ch) – case (c) or ch – ambient air (a) when mounting an infinite heat sink.

## What is the potential difference across the 4 ohm resistor?

Therefore, the potential difference across the 4-ohm resistor is 20 volts.

**What is Ohm’s law state?**

Ohm’s law states that the current through a conductor is proportional to the voltage across the conductor. V=IR where V is the voltage across the conductor and I is the current flowing through it.

**How is power dissipated by a resistor related to current?**

This correlation follows Ohm’s law, which states the formula for current as I (current) = V (voltage) ÷ R (resistance). In the field of electronics, power dissipation is also a measurement parameter that quantifies the releasing of heat within a circuit due to inefficiencies.

### What is the current through a 10 ohms resistor?

Ohm’s Law says that the current through the resistor is 10 v/2 Ohms= 2Amps. This cannot change. Right now all the 5A is coming from the voltage source. If you place a 2A constant current source across the circuit (across the resistor or voltage source that current flows through the voltage source.

**What is the Ohm’s law of voltage drop?**

Ohm’s law is V=IR where V is the voltage across the Resistor and I is the current through the resistor, and R is the resistance of the resistor. Therefore, the voltage drop across the Resistor is : (10A) x ( 2A) = 20V

**How to calculate current using voltage and resistance?**

When a voltage (V) and resistance are given, then you ought to use a formula for current. You can calculate current using the given formula! Current Formula: [Current (I) = Voltage (V) ÷ Resistance (R) ] I (amps) = V (volts) ÷ R (Ω) For Example: Find the current flowing through a 3 Ω resistor when a potential difference of 30 V is applied